(6x+1)(6x-1)(12x-1)(3x+1)=-18x^2

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Solution for (6x+1)(6x-1)(12x-1)(3x+1)=-18x^2 equation: 



(6x+1)(6x-1)(12x-1)(3x+1)=-18x^2

We move all terms to the left:

(6x+1)(6x-1)(12x-1)(3x+1)-(-18x^2)=0

We get rid of parentheses

18x^2+(6x+1)(6x-1)(12x-1)(3x+1)=0

We multiply parentheses ..

18x^2+(+36x^2-6x+6x-1)(12x-1)(3x+1)=0

We multiply parentheses ..

18x^2+(+36x^2-6x+6x-1)(+36x^2+12x-3x-1)=0

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